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x^2+12x-9180=0
a = 1; b = 12; c = -9180;
Δ = b2-4ac
Δ = 122-4·1·(-9180)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36864}=192$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-192}{2*1}=\frac{-204}{2} =-102 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+192}{2*1}=\frac{180}{2} =90 $
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